Question:
show that n{P[P.(P{})]}= 4
Answer:
We have P(Φ) = {Φ}
Now, P(P(Φ)) = {Φ, {Φ}}
Now, P(P(P(Φ))) = {Φ, {Φ}, {{Φ}}, {{Φ, {Φ}}}}
Hence, P(P(P(Φ))) contains 4 elements,
So, n{P(P(P(Φ)))} = 4
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